DEAR VIEWERS,
HERE ARE SOME PERCENTAGES BASED COMPLICATED PROBLEMS ASKED IN IBPS HAVE A NICE TIME
1. In an election, candidate A got 75% of the total valid votes. If 15% of the total votes were declared invalid and the total numbers of votes is 560000, find the number of valid vote polled in favour of candidate.
Solution:
Total number of invalid votes = 15 % of 560000
= 15/100 × 560000
= 8400000/100
= 84000
Total number of valid votes 560000 – 84000 = 476000
Percentage of votes polled in favour of candidate A = 75 %
Therefore, the number of valid votes polled in favour of candidate A = 75 % of 476000
= 75/100 × 476000
= 35700000/100
= 357000
2. A shopkeeper bought 600 oranges and 400 bananas. He found 15% of oranges and 8% of bananas were rotten. Find the percentage of fruits in good condition.
Solution:
Total number of fruits shopkeeper bought = 600 + 400 = 1000
Number of rotten oranges = 15% of 600
= 15/100 × 600
= 9000/100
= 90
Number of rotten bananas = 8% of 400
= 8/100 × 400
= 3200/100
= 32
Therefore, total number of rotten fruits = 90 + 32 = 122
Therefore Number of fruits in good condition = 1000 - 122 = 878
Therefore Percentage of fruits in good condition = (878/1000 × 100)%
= (87800/1000)%
= 87.8%
3. Aaron had $ 2100 left after spending 30 % of the money he took for shopping. How much money did he take along with him?
Solution:
Let the money he took for shopping be m.
Money he spent = 30 % of m
= 30/100 × m
= 3/10 m
Money left with him = m – 3/10 m = (10m – 3m)/10 = 7m/10
But money left with him = $ 2100
Therefore 7m/10 = $ 2100
m = $ 2100× 10/7
m = $ 21000/7
m = $ 3000
Therefore, the money he took for shopping is $ 3000.
4.A team lost 25 % of the matches it played. If it won 15 matches, find the number of matches it played.
Solution:
Percentage of matches lost = 25 %
Therefore Percentage of matches won (100 - 25) % = 75 %
Let the number of matches played be m.
Then 75 % of m = 15
75/100 × m = 15
m = (15 × 100)/75 %
m = (1500)/75 %
m = 20 %
Therefore, the total number of matches played is 20.
5. In a plot of 6000 sq. m., only 4500 sq. m. is allowed for construction. What percent of the plot is to be left without construction?
Solution:
Percentage of plot allowed for construction = (4500/6000 × 100) % = 75 %.
Thus, the percentage of plot to be left without construction = 100 % - 75 % = 25 %.
6. A number is reduced by 100 %. Its present value is 270. What was its original value?
Solution:
Original value is percentage = 100 %.
Reduce amount in percentage = 10 %
Therefore, Percent value in percentage = 100 % - 10 % = 90 %.
According to the problem,
90 % of original value = 270.
Therefore, 100 % of original value = 270/90 × 100 = 300.
Thus, the original value was 300.
7. A girl is scored 60 out of 75 in English, 60 out of 90 in mathematics and 80 out of 100 in Science. Find girls score as percentage:
(i) in Mathematics
(ii) in all the three subjects (on the whole).
Solution:
(i) Percentage scored in Mathematics = 60/90 × 100 %
= 6000/90 %
= 200/3 %
= 662/3 %
(ii) Total maximum of all the three subjects = 75 + 90 + 100 = 265 and
Total score in the three subjects = 60 + 60 + 80 = 200
Therefore, percentage on the whole = (200/265 × 100) %
= (20000/265) %
= 4000/65 %
= 7525/53 %
No comments:
Post a Comment